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X^2=364-12X
We move all terms to the left:
X^2-(364-12X)=0
We add all the numbers together, and all the variables
X^2-(-12X+364)=0
We get rid of parentheses
X^2+12X-364=0
a = 1; b = 12; c = -364;
Δ = b2-4ac
Δ = 122-4·1·(-364)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-40}{2*1}=\frac{-52}{2} =-26 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+40}{2*1}=\frac{28}{2} =14 $
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